1/x^2-10=35

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Solution for 1/x^2-10=35 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^2)-10 = 35 // - 35

1/(x^2)-35-10 = 0

1*x^-2 = 45 // : 1

x^-2 = 45

-2 < 0

1/(x^2) = 45 // * x^2

1 = 45*x^2 // : 45

1/45 = x^2

x^2 = 1/45 // ^ 1/2

abs(x) = (1/45)^(1/2)

x = (1/45)^(1/2) or x = -(1/45)^(1/2)

x in { (1/45)^(1/2), -(1/45)^(1/2) }

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